国家二级C语言典型题解析
有以下程序1void f(int a[], int i, int j)
{ int t;
if(i<j)
{ t=a; a=a; a=t;
f(a,i+1,j-1);
}
}
main()
{ int i, aa={1,2,3,4,5};
f(aa,0,4);
for(i=0; i<5; i++) printf("%d,",aa);printf("\n");
}
执行后输出结果是
A）5,4,3,2,1, B）5,2,3,4,1, C）1,2,3,4,5, D）1,5,4,3,2,
答案:A
解析:f(aa,0,4)调用是地址双向传递.i=0,j=4,交换aa=、aa的值使
aa={5,4,3,2,1};接着递归调用f(a,i+1,j-1)即f(a,1,3),交换aa、aa=的值使aa={5,4,3,2,1};接着递归调用f(a,i+1,j-1)即f(a,2,2),由于i=j=2,退出函数调用,依次输出aa的数组元素为"5,4,3,2,1,"
有以下程序2
struct STU
{ char name;
int num;
int Score;
};
main()
{ struct STU s={{"YangSan", 20041, 703},{"LiSiGuo", 20042, 580},
{"WangYin", 20043, 680},{"SunDan", 20044, 550},
{"Penghua", 20045, 537}}, *p, *t;
int i,j;
for(i=0; i<5; i++) p=&s;
for(i=0; i<4; i++)
for(j=i+1; j<5; j++)
if(p->Score > p->Score)
{ t=p; p=p; p=t;}
printf("%d %d\n", s.Score, p->Score);
}
执行后输出结果是
A）550 550 B）680 680 C）580 550 D）580 680
答案:C
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